3^2x-7*3^x=18

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Solution for 3^2x-7*3^x=18 equation: 



3^2x-7*3^x=18

We move all terms to the left:

3^2x-7*3^x-(18)=0

Wy multiply elements

3^2x-21x-18=0

We add all the numbers together, and all the variables

-21x+3^2x-18=0

We move all terms containing x to the left, all other terms to the right

-21x+3^2x=18

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